40 pts! Consider this quadratic equation. x^2+2x+7=21 The number of positive solutions to this equation is ____. The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is ____

x2 + 2x + 7 = 21Set it equal to zero by subtracting 21 from both sidesx2 + 2x + 7 - 21 = 21 - 21x2 + 2x - 14 = 0Use the quadratic equation: x = (-b +- ( b^2 - 4ac)^1/2)/2aIn our equation a = 1, b = 2 and c = - 14(-2 +-(4 + 56)^1/2)/2x = -1 +- (60^1/2)/2There is one positive solution to this equation and it is 2.87Hope it helps